1/2y+3y-2/3y^2-7

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Solution for 1/2y+3y-2/3y^2-7 equation: 


y in (-oo:+oo)

(1/2)*y-((2/3)*y^2)+3*y-7 = 0

(-2/3)*y^2+(1/2)*y+3*y-7 = 0

7/2*y-2/3*y^2-7 = 0

DELTA = (7/2)^2-(-7*(-2/3)*4)

DELTA = -77/12

DELTA < 0

y belongs to the empty set

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